Small Tidbits on Ark, Especially Mathematical

Baraminological Note · For Sea-Farers .... · Rolling Period of Ark? · Ark : empty weight and freighted weight, number of couples on the Ark. · Small Tidbits on Ark, Especially Mathematical

I

Someone - I think former JW The Truth Hurts - made the argument that all peoples who have a Flood story also have access to big water.

I have already argued, for the peoples in the Altai region, this is not true.

But here is more - nearly all countries in the world are with sea access. On wiki, List of sovereign states states:

The 206 listed states can be divided into three categories based on membership within the United Nations System: 193 member states,[1] 2 observer states, and 11 other states.

And the article Landlocked country states:

In 1990, there were only 30 landlocked countries in the world. The breakup of Yugoslavia, the dissolutions of the Soviet Union and Czechoslovakia, and the independence referendums of Eritrea and South Sudan have created 15 new landlocked countries and 4 partially recognized landlocked states while the former landlocked country of Czechoslovakia ceased to exist on 1 January 1993.

In other words, human populations overall have a tendency to have access to big waters.

II

Dimensions of wood on the ark were calculated in my article Ark : empty weight and freighted weight, number of couples on the Ark as if the "walls" of the container had no overlapping parts. This is not true. You have prisms:

4 * hind wall X horizontals
4 * front wall X horizontals
4 * right wall X horizontals
4 * left wall X horizontals
4 * long X short verticals only

And you have 16 cubes where these prisms intersect.

The proper maths to deal with a correction would be to first subtract the prisms and then add back the cubes. Why so?

Imagine you had only three walls. Three prisms belong to two walls each. These are therefore already accounted for twice, so you subtract them once, the one correct count being left. The cube where all three walls meet also belongs to the three prisms. It is added three times over, once in each wall, and subtracted three times over, once in each prism. It must therefore be added once to have the one correct count of its existence.

III

Executing previous corrections ... in order to get the right total volume (which is not our main concern), one would for each deduct the first three values and add the fourth one, but as deduction from volume of wood ultimately means addition of freight capacity, we well add the three and subtract the fourth (in order to get the volume one would then deduct the result from the volume).

For readability, I will approximate after three decimals and for the final result, we'll consider that the m³ of water = mt (metric ton).

Short cubit, thin walls

8 * hind/front walls X horizontals
8 * 22.86 m * 0.2286 m * 0.2286 m = 9.557 m³
8 * right/left walls X horizontals
8 * 137.16 m * 0.2286 m * 0.2286 m = 57.342 m³
4 * long X short (verticals only)
4 * 13.716 m * 0.2286 m * 0.2286 m = 2.867 m³
16 * 0.2286 m * 0.2286 m * 0.2286 m = 0.191 m³
9.557 m³ + 57.342 m³ + 2.867 m³ - 0.191 m³ = 69.574 m³ / mt

Short cubit, thick walls

8 * hind/front walls X horizontals
8 * 22.86 m * 0.4572 m * 0.4572 m = 38.228 m³
8 * right/left walls X horizontals
8 * 137.16 m * 0.4572 m * 0.4572 m = 229.366 m³
4 * long X short (verticals only)
4 * 13.716 m * 0.4572 m * 0.4572 m = 11.468 m³
16 * 0.4572 m * 0.4572 m * 0.4572 m = 1.529 m³
38.228 m³ + 229.366 m³ + 11.468 m³ - 1.529 m³ = 278.298 m³ / mt

Long cubit, thin walls

8 * hind/front walls X horizontals
8 * 30.48 m * 0.3048 m * 0.3048 m = 22.653 m³
8 * right/left walls X horizontals
8 * 182.88 m * 0.3048 m * 0.3048 m = 135.921 m³
4 * long X short (verticals only)
4 * 18.288 m * 0.3048 m * 0.3048 m = 6.796 m³
16 * 0.3048 m * 0.3048 m * 0.3048 m = 0.453 m³
22.653 m³ + 135.921 m³ + 6.796 m³ - 0.453 m³ = 164.917 m³ / mt

Long cubit, thick walls

8 * hind/front walls X horizontals
8 * 30.48 m * 0.6096 m * 0.6096 m = 90.614 m³
8 * right/left walls X horizontals
8 * 182.88 m * 0.6096 m * 0.6096 m = 543.683 m³
4 * long X short (verticals only)
4 * 18.288 m * 0.6096 m * 0.6096 m = 27.184 m³
16 * 0.6096 m * 0.6096 m * 0.6096 m = 3.625 m³
90.614 m³ + 543.683 m³ + 27.184 m³ - 3.625 m³ = 659.669 m³ / mt

IV

And now let's apply this to the freight capacity ... and let's stay with 14 cubits high water line, meaning we need not just to multiply above corrections with density, but also with 7/15:

Smallest weight available, biggest weight in walls, for small cubit:

20,069.565 - 6,812.184 = 13,257.381 mt
278.298 * 0.88 * 7/15 = 114.288 mt
13,257.381 + 114.288 = 13,371.669 mt

Biggest weight available, smallest weight in walls, for small cubit:

20,069.565 - 1,362.437 = 18,707.128 mt
69.574 * 0.352 * 7/15 = 11.429 mt
18,707.128 + 11.429 = 18,718.557 mt

Smallest weight available, biggest weight in walls, for big cubit:

47,572.302 - 16,147.399 = 31,424.904 mt
659.669 * 0.88 * 7/15 = 270.904 mt
31,424.904 + 270.904 = 31,695.808 mt

Biggest weight available, smallest weight in walls, for big cubit:

47,572.302 - 3,229.48 = 44,342.823 mt
164.917 * 0.352 * 7/15 = 27.09 mt
44,342.823 + 27.09 = 44,369.913 mt.

V

Revisiting two paragraphs:

On the other* post, I had estimated the number of couples to 2032, meaning 4064 individuals, on the average size of a sheep. Now, a sheep eats 7 kg green fodder per day, 365 days. 10,383.52 metric tons for food. How much would 4064 sheep weigh? Tame sheep weigh 45 to 160 kg for the bucks, 45 to 100 kg for the ewes. Let's add the numbers together and divide by four : (45+45+160+100)/4 = 87.5 kg. Let's multiply this by 4064. 355.6 metric tons. Living passengers with crew therefore 355.6 + 10,383.52 = 10,739.12.

So, even the smallest weight available for the animals and food and tools and the walls of the small chambers and so on has 500 tons for tools and temporary water supplies on top of needed animals and food weight. And the 2032 couples I got by reducing an evolutionist's estimate for number of species (taking mammals, birds, reptiles and amphibians separately) by only 16, the number of species I thought there were of hedgehogs, but that's actually 17.

13,371.669 - 10,739.12 = 2632.549 mt
18,718.557 - 10,739.12 = 7979.437 mt

All that for tools and water?

I think there might actually have been more animals than just 2032 couples. Especially since 7 kg food per day is not exactly typical in proportion to the body weight, the ruminants need more food.

And this would mean, hedgehogs are more diversified as a baramin than the medium.

Hans Georg Lundahl
Paris
St. Josaphat
12.XI.2021

Vitepsci, in Polonia, passio sancti Josaphat, e sancti Basilii Ordine, Episcopi Polocensis et Martyris; qui a schismaticis, in odium catholicae unitatis et veritatis, crudeliter interfectus est, et a Pio Papa Nono inter sanctos Martyres adscriptus. Ejus tamen festivitas recolitur decimo octavo Kalendas Decembris.